Geometry and topology · Oct 6, 2026

A counterexample to Griffiths’ positivity conjecture

Constructs ample rank-two bundles on P1×P1\mathbb P^1\times\mathbb P^1 with no smooth Hermitian metric of strictly Griffiths-positive curvature, disproving Griffiths' positivity conjecture already on the quadric surface.

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